What are the required steps to convert base 10 decimal system
number 1 490 151 to base 2 unsigned binary equivalent?
- A number written in base ten, or a decimal system number, is a number written using the digits 0 through 9. A number written in base two, or a binary system number, is a number written using only the digits 0 and 1.
1. Divide the number repeatedly by 2:
Keep track of each remainder.
Stop when you get a quotient that is equal to zero.
- division = quotient + remainder;
- 1 490 151 ÷ 2 = 745 075 + 1;
- 745 075 ÷ 2 = 372 537 + 1;
- 372 537 ÷ 2 = 186 268 + 1;
- 186 268 ÷ 2 = 93 134 + 0;
- 93 134 ÷ 2 = 46 567 + 0;
- 46 567 ÷ 2 = 23 283 + 1;
- 23 283 ÷ 2 = 11 641 + 1;
- 11 641 ÷ 2 = 5 820 + 1;
- 5 820 ÷ 2 = 2 910 + 0;
- 2 910 ÷ 2 = 1 455 + 0;
- 1 455 ÷ 2 = 727 + 1;
- 727 ÷ 2 = 363 + 1;
- 363 ÷ 2 = 181 + 1;
- 181 ÷ 2 = 90 + 1;
- 90 ÷ 2 = 45 + 0;
- 45 ÷ 2 = 22 + 1;
- 22 ÷ 2 = 11 + 0;
- 11 ÷ 2 = 5 + 1;
- 5 ÷ 2 = 2 + 1;
- 2 ÷ 2 = 1 + 0;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
1 490 151(10) Base 10 decimal system number converted and written as a base 2 unsigned binary equivalent:
1 490 151 (base 10) = 1 0110 1011 1100 1110 0111 (base 2)
Spaces were used to group digits: for binary, by 4, for decimal, by 3.