What are the required steps to convert base 10 decimal system
number 1 488 079 to base 2 unsigned binary equivalent?
- A number written in base ten, or a decimal system number, is a number written using the digits 0 through 9. A number written in base two, or a binary system number, is a number written using only the digits 0 and 1.
1. Divide the number repeatedly by 2:
Keep track of each remainder.
Stop when you get a quotient that is equal to zero.
- division = quotient + remainder;
- 1 488 079 ÷ 2 = 744 039 + 1;
- 744 039 ÷ 2 = 372 019 + 1;
- 372 019 ÷ 2 = 186 009 + 1;
- 186 009 ÷ 2 = 93 004 + 1;
- 93 004 ÷ 2 = 46 502 + 0;
- 46 502 ÷ 2 = 23 251 + 0;
- 23 251 ÷ 2 = 11 625 + 1;
- 11 625 ÷ 2 = 5 812 + 1;
- 5 812 ÷ 2 = 2 906 + 0;
- 2 906 ÷ 2 = 1 453 + 0;
- 1 453 ÷ 2 = 726 + 1;
- 726 ÷ 2 = 363 + 0;
- 363 ÷ 2 = 181 + 1;
- 181 ÷ 2 = 90 + 1;
- 90 ÷ 2 = 45 + 0;
- 45 ÷ 2 = 22 + 1;
- 22 ÷ 2 = 11 + 0;
- 11 ÷ 2 = 5 + 1;
- 5 ÷ 2 = 2 + 1;
- 2 ÷ 2 = 1 + 0;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
1 488 079(10) Base 10 decimal system number converted and written as a base 2 unsigned binary equivalent:
1 488 079 (base 10) = 1 0110 1011 0100 1100 1111 (base 2)
Spaces were used to group digits: for binary, by 4, for decimal, by 3.