What are the required steps to convert base 10 decimal system
number 14 680 311 to base 2 unsigned binary equivalent?
- A number written in base ten, or a decimal system number, is a number written using the digits 0 through 9. A number written in base two, or a binary system number, is a number written using only the digits 0 and 1.
1. Divide the number repeatedly by 2:
Keep track of each remainder.
Stop when you get a quotient that is equal to zero.
- division = quotient + remainder;
- 14 680 311 ÷ 2 = 7 340 155 + 1;
- 7 340 155 ÷ 2 = 3 670 077 + 1;
- 3 670 077 ÷ 2 = 1 835 038 + 1;
- 1 835 038 ÷ 2 = 917 519 + 0;
- 917 519 ÷ 2 = 458 759 + 1;
- 458 759 ÷ 2 = 229 379 + 1;
- 229 379 ÷ 2 = 114 689 + 1;
- 114 689 ÷ 2 = 57 344 + 1;
- 57 344 ÷ 2 = 28 672 + 0;
- 28 672 ÷ 2 = 14 336 + 0;
- 14 336 ÷ 2 = 7 168 + 0;
- 7 168 ÷ 2 = 3 584 + 0;
- 3 584 ÷ 2 = 1 792 + 0;
- 1 792 ÷ 2 = 896 + 0;
- 896 ÷ 2 = 448 + 0;
- 448 ÷ 2 = 224 + 0;
- 224 ÷ 2 = 112 + 0;
- 112 ÷ 2 = 56 + 0;
- 56 ÷ 2 = 28 + 0;
- 28 ÷ 2 = 14 + 0;
- 14 ÷ 2 = 7 + 0;
- 7 ÷ 2 = 3 + 1;
- 3 ÷ 2 = 1 + 1;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
14 680 311(10) Base 10 decimal system number converted and written as a base 2 unsigned binary equivalent:
14 680 311 (base 10) = 1110 0000 0000 0000 1111 0111 (base 2)
Spaces were used to group digits: for binary, by 4, for decimal, by 3.