What are the required steps to convert base 10 decimal system
number 13 490 306 to base 2 unsigned binary equivalent?
- A number written in base ten, or a decimal system number, is a number written using the digits 0 through 9. A number written in base two, or a binary system number, is a number written using only the digits 0 and 1.
1. Divide the number repeatedly by 2:
Keep track of each remainder.
Stop when you get a quotient that is equal to zero.
- division = quotient + remainder;
- 13 490 306 ÷ 2 = 6 745 153 + 0;
- 6 745 153 ÷ 2 = 3 372 576 + 1;
- 3 372 576 ÷ 2 = 1 686 288 + 0;
- 1 686 288 ÷ 2 = 843 144 + 0;
- 843 144 ÷ 2 = 421 572 + 0;
- 421 572 ÷ 2 = 210 786 + 0;
- 210 786 ÷ 2 = 105 393 + 0;
- 105 393 ÷ 2 = 52 696 + 1;
- 52 696 ÷ 2 = 26 348 + 0;
- 26 348 ÷ 2 = 13 174 + 0;
- 13 174 ÷ 2 = 6 587 + 0;
- 6 587 ÷ 2 = 3 293 + 1;
- 3 293 ÷ 2 = 1 646 + 1;
- 1 646 ÷ 2 = 823 + 0;
- 823 ÷ 2 = 411 + 1;
- 411 ÷ 2 = 205 + 1;
- 205 ÷ 2 = 102 + 1;
- 102 ÷ 2 = 51 + 0;
- 51 ÷ 2 = 25 + 1;
- 25 ÷ 2 = 12 + 1;
- 12 ÷ 2 = 6 + 0;
- 6 ÷ 2 = 3 + 0;
- 3 ÷ 2 = 1 + 1;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
13 490 306(10) Base 10 decimal system number converted and written as a base 2 unsigned binary equivalent:
13 490 306 (base 10) = 1100 1101 1101 1000 1000 0010 (base 2)
Spaces were used to group digits: for binary, by 4, for decimal, by 3.