What are the required steps to convert base 10 decimal system
number 13 021 947 to base 2 unsigned binary equivalent?
- A number written in base ten, or a decimal system number, is a number written using the digits 0 through 9. A number written in base two, or a binary system number, is a number written using only the digits 0 and 1.
1. Divide the number repeatedly by 2:
Keep track of each remainder.
Stop when you get a quotient that is equal to zero.
- division = quotient + remainder;
- 13 021 947 ÷ 2 = 6 510 973 + 1;
- 6 510 973 ÷ 2 = 3 255 486 + 1;
- 3 255 486 ÷ 2 = 1 627 743 + 0;
- 1 627 743 ÷ 2 = 813 871 + 1;
- 813 871 ÷ 2 = 406 935 + 1;
- 406 935 ÷ 2 = 203 467 + 1;
- 203 467 ÷ 2 = 101 733 + 1;
- 101 733 ÷ 2 = 50 866 + 1;
- 50 866 ÷ 2 = 25 433 + 0;
- 25 433 ÷ 2 = 12 716 + 1;
- 12 716 ÷ 2 = 6 358 + 0;
- 6 358 ÷ 2 = 3 179 + 0;
- 3 179 ÷ 2 = 1 589 + 1;
- 1 589 ÷ 2 = 794 + 1;
- 794 ÷ 2 = 397 + 0;
- 397 ÷ 2 = 198 + 1;
- 198 ÷ 2 = 99 + 0;
- 99 ÷ 2 = 49 + 1;
- 49 ÷ 2 = 24 + 1;
- 24 ÷ 2 = 12 + 0;
- 12 ÷ 2 = 6 + 0;
- 6 ÷ 2 = 3 + 0;
- 3 ÷ 2 = 1 + 1;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
13 021 947(10) Base 10 decimal system number converted and written as a base 2 unsigned binary equivalent:
13 021 947 (base 10) = 1100 0110 1011 0010 1111 1011 (base 2)
Spaces were used to group digits: for binary, by 4, for decimal, by 3.