What are the required steps to convert base 10 decimal system
number 1 249 558 to base 2 unsigned binary equivalent?
- A number written in base ten, or a decimal system number, is a number written using the digits 0 through 9. A number written in base two, or a binary system number, is a number written using only the digits 0 and 1.
1. Divide the number repeatedly by 2:
Keep track of each remainder.
Stop when you get a quotient that is equal to zero.
- division = quotient + remainder;
- 1 249 558 ÷ 2 = 624 779 + 0;
- 624 779 ÷ 2 = 312 389 + 1;
- 312 389 ÷ 2 = 156 194 + 1;
- 156 194 ÷ 2 = 78 097 + 0;
- 78 097 ÷ 2 = 39 048 + 1;
- 39 048 ÷ 2 = 19 524 + 0;
- 19 524 ÷ 2 = 9 762 + 0;
- 9 762 ÷ 2 = 4 881 + 0;
- 4 881 ÷ 2 = 2 440 + 1;
- 2 440 ÷ 2 = 1 220 + 0;
- 1 220 ÷ 2 = 610 + 0;
- 610 ÷ 2 = 305 + 0;
- 305 ÷ 2 = 152 + 1;
- 152 ÷ 2 = 76 + 0;
- 76 ÷ 2 = 38 + 0;
- 38 ÷ 2 = 19 + 0;
- 19 ÷ 2 = 9 + 1;
- 9 ÷ 2 = 4 + 1;
- 4 ÷ 2 = 2 + 0;
- 2 ÷ 2 = 1 + 0;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
1 249 558(10) Base 10 decimal system number converted and written as a base 2 unsigned binary equivalent:
1 249 558 (base 10) = 1 0011 0001 0001 0001 0110 (base 2)
Spaces were used to group digits: for binary, by 4, for decimal, by 3.