What are the required steps to convert base 10 decimal system
number 1 237 630 to base 2 unsigned binary equivalent?
- A number written in base ten, or a decimal system number, is a number written using the digits 0 through 9. A number written in base two, or a binary system number, is a number written using only the digits 0 and 1.
1. Divide the number repeatedly by 2:
Keep track of each remainder.
Stop when you get a quotient that is equal to zero.
- division = quotient + remainder;
- 1 237 630 ÷ 2 = 618 815 + 0;
- 618 815 ÷ 2 = 309 407 + 1;
- 309 407 ÷ 2 = 154 703 + 1;
- 154 703 ÷ 2 = 77 351 + 1;
- 77 351 ÷ 2 = 38 675 + 1;
- 38 675 ÷ 2 = 19 337 + 1;
- 19 337 ÷ 2 = 9 668 + 1;
- 9 668 ÷ 2 = 4 834 + 0;
- 4 834 ÷ 2 = 2 417 + 0;
- 2 417 ÷ 2 = 1 208 + 1;
- 1 208 ÷ 2 = 604 + 0;
- 604 ÷ 2 = 302 + 0;
- 302 ÷ 2 = 151 + 0;
- 151 ÷ 2 = 75 + 1;
- 75 ÷ 2 = 37 + 1;
- 37 ÷ 2 = 18 + 1;
- 18 ÷ 2 = 9 + 0;
- 9 ÷ 2 = 4 + 1;
- 4 ÷ 2 = 2 + 0;
- 2 ÷ 2 = 1 + 0;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
1 237 630(10) Base 10 decimal system number converted and written as a base 2 unsigned binary equivalent:
1 237 630 (base 10) = 1 0010 1110 0010 0111 1110 (base 2)
Spaces were used to group digits: for binary, by 4, for decimal, by 3.