What are the required steps to convert base 10 decimal system
number 1 149 978 to base 2 unsigned binary equivalent?
- A number written in base ten, or a decimal system number, is a number written using the digits 0 through 9. A number written in base two, or a binary system number, is a number written using only the digits 0 and 1.
1. Divide the number repeatedly by 2:
Keep track of each remainder.
Stop when you get a quotient that is equal to zero.
- division = quotient + remainder;
- 1 149 978 ÷ 2 = 574 989 + 0;
- 574 989 ÷ 2 = 287 494 + 1;
- 287 494 ÷ 2 = 143 747 + 0;
- 143 747 ÷ 2 = 71 873 + 1;
- 71 873 ÷ 2 = 35 936 + 1;
- 35 936 ÷ 2 = 17 968 + 0;
- 17 968 ÷ 2 = 8 984 + 0;
- 8 984 ÷ 2 = 4 492 + 0;
- 4 492 ÷ 2 = 2 246 + 0;
- 2 246 ÷ 2 = 1 123 + 0;
- 1 123 ÷ 2 = 561 + 1;
- 561 ÷ 2 = 280 + 1;
- 280 ÷ 2 = 140 + 0;
- 140 ÷ 2 = 70 + 0;
- 70 ÷ 2 = 35 + 0;
- 35 ÷ 2 = 17 + 1;
- 17 ÷ 2 = 8 + 1;
- 8 ÷ 2 = 4 + 0;
- 4 ÷ 2 = 2 + 0;
- 2 ÷ 2 = 1 + 0;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
1 149 978(10) Base 10 decimal system number converted and written as a base 2 unsigned binary equivalent:
1 149 978 (base 10) = 1 0001 1000 1100 0001 1010 (base 2)
Spaces were used to group digits: for binary, by 4, for decimal, by 3.