What are the required steps to convert base 10 decimal system
number 1 101 000 100 133 to base 2 unsigned binary equivalent?
- A number written in base ten, or a decimal system number, is a number written using the digits 0 through 9. A number written in base two, or a binary system number, is a number written using only the digits 0 and 1.
1. Divide the number repeatedly by 2:
Keep track of each remainder.
Stop when you get a quotient that is equal to zero.
- division = quotient + remainder;
- 1 101 000 100 133 ÷ 2 = 550 500 050 066 + 1;
- 550 500 050 066 ÷ 2 = 275 250 025 033 + 0;
- 275 250 025 033 ÷ 2 = 137 625 012 516 + 1;
- 137 625 012 516 ÷ 2 = 68 812 506 258 + 0;
- 68 812 506 258 ÷ 2 = 34 406 253 129 + 0;
- 34 406 253 129 ÷ 2 = 17 203 126 564 + 1;
- 17 203 126 564 ÷ 2 = 8 601 563 282 + 0;
- 8 601 563 282 ÷ 2 = 4 300 781 641 + 0;
- 4 300 781 641 ÷ 2 = 2 150 390 820 + 1;
- 2 150 390 820 ÷ 2 = 1 075 195 410 + 0;
- 1 075 195 410 ÷ 2 = 537 597 705 + 0;
- 537 597 705 ÷ 2 = 268 798 852 + 1;
- 268 798 852 ÷ 2 = 134 399 426 + 0;
- 134 399 426 ÷ 2 = 67 199 713 + 0;
- 67 199 713 ÷ 2 = 33 599 856 + 1;
- 33 599 856 ÷ 2 = 16 799 928 + 0;
- 16 799 928 ÷ 2 = 8 399 964 + 0;
- 8 399 964 ÷ 2 = 4 199 982 + 0;
- 4 199 982 ÷ 2 = 2 099 991 + 0;
- 2 099 991 ÷ 2 = 1 049 995 + 1;
- 1 049 995 ÷ 2 = 524 997 + 1;
- 524 997 ÷ 2 = 262 498 + 1;
- 262 498 ÷ 2 = 131 249 + 0;
- 131 249 ÷ 2 = 65 624 + 1;
- 65 624 ÷ 2 = 32 812 + 0;
- 32 812 ÷ 2 = 16 406 + 0;
- 16 406 ÷ 2 = 8 203 + 0;
- 8 203 ÷ 2 = 4 101 + 1;
- 4 101 ÷ 2 = 2 050 + 1;
- 2 050 ÷ 2 = 1 025 + 0;
- 1 025 ÷ 2 = 512 + 1;
- 512 ÷ 2 = 256 + 0;
- 256 ÷ 2 = 128 + 0;
- 128 ÷ 2 = 64 + 0;
- 64 ÷ 2 = 32 + 0;
- 32 ÷ 2 = 16 + 0;
- 16 ÷ 2 = 8 + 0;
- 8 ÷ 2 = 4 + 0;
- 4 ÷ 2 = 2 + 0;
- 2 ÷ 2 = 1 + 0;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
1 101 000 100 133(10) Base 10 decimal system number converted and written as a base 2 unsigned binary equivalent:
1 101 000 100 133 (base 10) = 1 0000 0000 0101 1000 1011 1000 0100 1001 0010 0101 (base 2)
Spaces were used to group digits: for binary, by 4, for decimal, by 3.