Unsigned: Integer ↗ Binary: 110 000 110 101 000 130 Convert the Positive Integer (Whole Number) From Base Ten (10) To Base Two (2), Conversion and Writing of Decimal System Number as Unsigned Binary Code

Unsigned (positive) integer number 110 000 110 101 000 130(10)
converted and written as an unsigned binary (base 2) = ?

1. Divide the number repeatedly by 2:

Keep track of each remainder.

We stop when we get a quotient that is equal to zero.

  • division = quotient + remainder;
  • 110 000 110 101 000 130 ÷ 2 = 55 000 055 050 500 065 + 0;
  • 55 000 055 050 500 065 ÷ 2 = 27 500 027 525 250 032 + 1;
  • 27 500 027 525 250 032 ÷ 2 = 13 750 013 762 625 016 + 0;
  • 13 750 013 762 625 016 ÷ 2 = 6 875 006 881 312 508 + 0;
  • 6 875 006 881 312 508 ÷ 2 = 3 437 503 440 656 254 + 0;
  • 3 437 503 440 656 254 ÷ 2 = 1 718 751 720 328 127 + 0;
  • 1 718 751 720 328 127 ÷ 2 = 859 375 860 164 063 + 1;
  • 859 375 860 164 063 ÷ 2 = 429 687 930 082 031 + 1;
  • 429 687 930 082 031 ÷ 2 = 214 843 965 041 015 + 1;
  • 214 843 965 041 015 ÷ 2 = 107 421 982 520 507 + 1;
  • 107 421 982 520 507 ÷ 2 = 53 710 991 260 253 + 1;
  • 53 710 991 260 253 ÷ 2 = 26 855 495 630 126 + 1;
  • 26 855 495 630 126 ÷ 2 = 13 427 747 815 063 + 0;
  • 13 427 747 815 063 ÷ 2 = 6 713 873 907 531 + 1;
  • 6 713 873 907 531 ÷ 2 = 3 356 936 953 765 + 1;
  • 3 356 936 953 765 ÷ 2 = 1 678 468 476 882 + 1;
  • 1 678 468 476 882 ÷ 2 = 839 234 238 441 + 0;
  • 839 234 238 441 ÷ 2 = 419 617 119 220 + 1;
  • 419 617 119 220 ÷ 2 = 209 808 559 610 + 0;
  • 209 808 559 610 ÷ 2 = 104 904 279 805 + 0;
  • 104 904 279 805 ÷ 2 = 52 452 139 902 + 1;
  • 52 452 139 902 ÷ 2 = 26 226 069 951 + 0;
  • 26 226 069 951 ÷ 2 = 13 113 034 975 + 1;
  • 13 113 034 975 ÷ 2 = 6 556 517 487 + 1;
  • 6 556 517 487 ÷ 2 = 3 278 258 743 + 1;
  • 3 278 258 743 ÷ 2 = 1 639 129 371 + 1;
  • 1 639 129 371 ÷ 2 = 819 564 685 + 1;
  • 819 564 685 ÷ 2 = 409 782 342 + 1;
  • 409 782 342 ÷ 2 = 204 891 171 + 0;
  • 204 891 171 ÷ 2 = 102 445 585 + 1;
  • 102 445 585 ÷ 2 = 51 222 792 + 1;
  • 51 222 792 ÷ 2 = 25 611 396 + 0;
  • 25 611 396 ÷ 2 = 12 805 698 + 0;
  • 12 805 698 ÷ 2 = 6 402 849 + 0;
  • 6 402 849 ÷ 2 = 3 201 424 + 1;
  • 3 201 424 ÷ 2 = 1 600 712 + 0;
  • 1 600 712 ÷ 2 = 800 356 + 0;
  • 800 356 ÷ 2 = 400 178 + 0;
  • 400 178 ÷ 2 = 200 089 + 0;
  • 200 089 ÷ 2 = 100 044 + 1;
  • 100 044 ÷ 2 = 50 022 + 0;
  • 50 022 ÷ 2 = 25 011 + 0;
  • 25 011 ÷ 2 = 12 505 + 1;
  • 12 505 ÷ 2 = 6 252 + 1;
  • 6 252 ÷ 2 = 3 126 + 0;
  • 3 126 ÷ 2 = 1 563 + 0;
  • 1 563 ÷ 2 = 781 + 1;
  • 781 ÷ 2 = 390 + 1;
  • 390 ÷ 2 = 195 + 0;
  • 195 ÷ 2 = 97 + 1;
  • 97 ÷ 2 = 48 + 1;
  • 48 ÷ 2 = 24 + 0;
  • 24 ÷ 2 = 12 + 0;
  • 12 ÷ 2 = 6 + 0;
  • 6 ÷ 2 = 3 + 0;
  • 3 ÷ 2 = 1 + 1;
  • 1 ÷ 2 = 0 + 1;

2. Construct the base 2 representation of the positive number:

Take all the remainders starting from the bottom of the list constructed above.


Number 110 000 110 101 000 130(10), a positive integer number (with no sign),
converted from decimal system (from base 10)
and written as an unsigned binary (in base 2):

110 000 110 101 000 130(10) = 1 1000 0110 1100 1100 1000 0100 0110 1111 1101 0010 1110 1111 1100 0010(2)

Spaces were used to group digits: for binary, by 4, for decimal, by 3.

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How to convert unsigned integer numbers (positive) from decimal system (base 10) to binary = simply convert from base ten to base two

Follow the steps below to convert a base ten unsigned integer number to base two:

  • 1. Divide repeatedly by 2 the positive integer number that has to be converted to binary, keeping track of each remainder, until we get a QUOTIENT that is equal to ZERO.
  • 2. Construct the base 2 representation of the positive integer number, by taking all the remainders starting from the bottom of the list constructed above. Thus, the last remainder of the divisions becomes the first symbol (the leftmost) of the base two number, while the first remainder becomes the last symbol (the rightmost).

Example: convert the positive integer number 55 from decimal system (base ten) to binary code (base two):

  • 1. Divide repeatedly 55 by 2, keeping track of each remainder, until we get a quotient that is equal to zero:
    • division = quotient + remainder;
    • 55 ÷ 2 = 27 + 1;
    • 27 ÷ 2 = 13 + 1;
    • 13 ÷ 2 = 6 + 1;
    • 6 ÷ 2 = 3 + 0;
    • 3 ÷ 2 = 1 + 1;
    • 1 ÷ 2 = 0 + 1;
  • 2. Construct the base 2 representation of the positive integer number, by taking all the remainders starting from the bottom of the list constructed above:
    55(10) = 11 0111(2)
  • Number 5510, positive integer (no sign), converted from decimal system (base 10) to unsigned binary (base 2) = 11 0111(2)