Unsigned: Integer ↗ Binary: 1 000 011 000 011 028 Convert the Positive Integer (Whole Number) From Base Ten (10) To Base Two (2), Conversion and Writing of Decimal System Number as Unsigned Binary Code

Unsigned (positive) integer number 1 000 011 000 011 028(10)
converted and written as an unsigned binary (base 2) = ?

1. Divide the number repeatedly by 2:

Keep track of each remainder.

We stop when we get a quotient that is equal to zero.

  • division = quotient + remainder;
  • 1 000 011 000 011 028 ÷ 2 = 500 005 500 005 514 + 0;
  • 500 005 500 005 514 ÷ 2 = 250 002 750 002 757 + 0;
  • 250 002 750 002 757 ÷ 2 = 125 001 375 001 378 + 1;
  • 125 001 375 001 378 ÷ 2 = 62 500 687 500 689 + 0;
  • 62 500 687 500 689 ÷ 2 = 31 250 343 750 344 + 1;
  • 31 250 343 750 344 ÷ 2 = 15 625 171 875 172 + 0;
  • 15 625 171 875 172 ÷ 2 = 7 812 585 937 586 + 0;
  • 7 812 585 937 586 ÷ 2 = 3 906 292 968 793 + 0;
  • 3 906 292 968 793 ÷ 2 = 1 953 146 484 396 + 1;
  • 1 953 146 484 396 ÷ 2 = 976 573 242 198 + 0;
  • 976 573 242 198 ÷ 2 = 488 286 621 099 + 0;
  • 488 286 621 099 ÷ 2 = 244 143 310 549 + 1;
  • 244 143 310 549 ÷ 2 = 122 071 655 274 + 1;
  • 122 071 655 274 ÷ 2 = 61 035 827 637 + 0;
  • 61 035 827 637 ÷ 2 = 30 517 913 818 + 1;
  • 30 517 913 818 ÷ 2 = 15 258 956 909 + 0;
  • 15 258 956 909 ÷ 2 = 7 629 478 454 + 1;
  • 7 629 478 454 ÷ 2 = 3 814 739 227 + 0;
  • 3 814 739 227 ÷ 2 = 1 907 369 613 + 1;
  • 1 907 369 613 ÷ 2 = 953 684 806 + 1;
  • 953 684 806 ÷ 2 = 476 842 403 + 0;
  • 476 842 403 ÷ 2 = 238 421 201 + 1;
  • 238 421 201 ÷ 2 = 119 210 600 + 1;
  • 119 210 600 ÷ 2 = 59 605 300 + 0;
  • 59 605 300 ÷ 2 = 29 802 650 + 0;
  • 29 802 650 ÷ 2 = 14 901 325 + 0;
  • 14 901 325 ÷ 2 = 7 450 662 + 1;
  • 7 450 662 ÷ 2 = 3 725 331 + 0;
  • 3 725 331 ÷ 2 = 1 862 665 + 1;
  • 1 862 665 ÷ 2 = 931 332 + 1;
  • 931 332 ÷ 2 = 465 666 + 0;
  • 465 666 ÷ 2 = 232 833 + 0;
  • 232 833 ÷ 2 = 116 416 + 1;
  • 116 416 ÷ 2 = 58 208 + 0;
  • 58 208 ÷ 2 = 29 104 + 0;
  • 29 104 ÷ 2 = 14 552 + 0;
  • 14 552 ÷ 2 = 7 276 + 0;
  • 7 276 ÷ 2 = 3 638 + 0;
  • 3 638 ÷ 2 = 1 819 + 0;
  • 1 819 ÷ 2 = 909 + 1;
  • 909 ÷ 2 = 454 + 1;
  • 454 ÷ 2 = 227 + 0;
  • 227 ÷ 2 = 113 + 1;
  • 113 ÷ 2 = 56 + 1;
  • 56 ÷ 2 = 28 + 0;
  • 28 ÷ 2 = 14 + 0;
  • 14 ÷ 2 = 7 + 0;
  • 7 ÷ 2 = 3 + 1;
  • 3 ÷ 2 = 1 + 1;
  • 1 ÷ 2 = 0 + 1;

2. Construct the base 2 representation of the positive number:

Take all the remainders starting from the bottom of the list constructed above.


Number 1 000 011 000 011 028(10), a positive integer number (with no sign),
converted from decimal system (from base 10)
and written as an unsigned binary (in base 2):

1 000 011 000 011 028(10) = 11 1000 1101 1000 0001 0011 0100 0110 1101 0101 1001 0001 0100(2)

Spaces were used to group digits: for binary, by 4, for decimal, by 3.

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All the decimal system (written in base ten) positive integers (with no sign) converted to unsigned binary (in base 2)

How to convert unsigned integer numbers (positive) from decimal system (base 10) to binary = simply convert from base ten to base two

Follow the steps below to convert a base ten unsigned integer number to base two:

  • 1. Divide repeatedly by 2 the positive integer number that has to be converted to binary, keeping track of each remainder, until we get a QUOTIENT that is equal to ZERO.
  • 2. Construct the base 2 representation of the positive integer number, by taking all the remainders starting from the bottom of the list constructed above. Thus, the last remainder of the divisions becomes the first symbol (the leftmost) of the base two number, while the first remainder becomes the last symbol (the rightmost).

Example: convert the positive integer number 55 from decimal system (base ten) to binary code (base two):

  • 1. Divide repeatedly 55 by 2, keeping track of each remainder, until we get a quotient that is equal to zero:
    • division = quotient + remainder;
    • 55 ÷ 2 = 27 + 1;
    • 27 ÷ 2 = 13 + 1;
    • 13 ÷ 2 = 6 + 1;
    • 6 ÷ 2 = 3 + 0;
    • 3 ÷ 2 = 1 + 1;
    • 1 ÷ 2 = 0 + 1;
  • 2. Construct the base 2 representation of the positive integer number, by taking all the remainders starting from the bottom of the list constructed above:
    55(10) = 11 0111(2)
  • Number 5510, positive integer (no sign), converted from decimal system (base 10) to unsigned binary (base 2) = 11 0111(2)