2. Multiply each bit by its corresponding power of 2 and add all the terms up.
110 1111 1100 0010 1000 1110 0100 0101 0100(2) =
(1 × 234 + 1 × 233 + 0 × 232 + 1 × 231 + 1 × 230 + 1 × 229 + 1 × 228 + 1 × 227 + 1 × 226 + 0 × 225 + 0 × 224 + 0 × 223 + 0 × 222 + 1 × 221 + 0 × 220 + 1 × 219 + 0 × 218 + 0 × 217 + 0 × 216 + 1 × 215 + 1 × 214 + 1 × 213 + 0 × 212 + 0 × 211 + 1 × 210 + 0 × 29 + 0 × 28 + 0 × 27 + 1 × 26 + 0 × 25 + 1 × 24 + 0 × 23 + 1 × 22 + 0 × 21 + 0 × 20)(10) =
(17 179 869 184 + 8 589 934 592 + 0 + 2 147 483 648 + 1 073 741 824 + 536 870 912 + 268 435 456 + 134 217 728 + 67 108 864 + 0 + 0 + 0 + 0 + 2 097 152 + 0 + 524 288 + 0 + 0 + 0 + 32 768 + 16 384 + 8 192 + 0 + 0 + 1 024 + 0 + 0 + 0 + 64 + 0 + 16 + 0 + 4 + 0 + 0)(10) =
(17 179 869 184 + 8 589 934 592 + 2 147 483 648 + 1 073 741 824 + 536 870 912 + 268 435 456 + 134 217 728 + 67 108 864 + 2 097 152 + 524 288 + 32 768 + 16 384 + 8 192 + 1 024 + 64 + 16 + 4)(10) =
30 000 342 100(10)
The number 110 1111 1100 0010 1000 1110 0100 0101 0100(2) converted from an unsigned binary (in base 2) and written as a positive integer (with no sign) in decimal system (in base ten):
110 1111 1100 0010 1000 1110 0100 0101 0100(2) = 30 000 342 100(10)
Spaces were used to group digits: for binary, by 4, for decimal, by 3.