#### In a signed binary in one's complement representation, the first bit (the leftmost) indicates the sign, 1 = negative, 0 = positive.

### 2. Get the binary representation of the positive (unsigned) number.

#### * Run this step only if the number is negative *

#### Flip all the bits of the signed binary in one's complement representation (reverse the digits) - replace the bits set on 1 with 0s and the bits on 0 with 1s:

#### * Not the case - the number is positive *

### 3. Map the unsigned binary number's digits versus the corresponding powers of 2 that their place value represent:

2^{31}

0 2^{30}

0 2^{29}

0 2^{28}

0 2^{27}

0 2^{26}

0 2^{25}

0 2^{24}

0 2^{23}

0 2^{22}

0 2^{21}

0 2^{20}

0 2^{19}

0 2^{18}

0 2^{17}

1 2^{16}

1 2^{15}

1 2^{14}

1 2^{13}

1 2^{12}

1 2^{11}

1 2^{10}

1 2^{9}

1 2^{8}

1 2^{7}

1 2^{6}

1 2^{5}

1 2^{4}

1 2^{3}

1 2^{2}

0 2^{1}

1 2^{0}

1

### 4. Multiply each bit by its corresponding power of 2 and add all the terms up.

#### 0000 0000 0000 0011 1111 1111 1111 1011_{(2)} =

#### (0 × 2^{31} + 0 × 2^{30} + 0 × 2^{29} + 0 × 2^{28} + 0 × 2^{27} + 0 × 2^{26} + 0 × 2^{25} + 0 × 2^{24} + 0 × 2^{23} + 0 × 2^{22} + 0 × 2^{21} + 0 × 2^{20} + 0 × 2^{19} + 0 × 2^{18} + 1 × 2^{17} + 1 × 2^{16} + 1 × 2^{15} + 1 × 2^{14} + 1 × 2^{13} + 1 × 2^{12} + 1 × 2^{11} + 1 × 2^{10} + 1 × 2^{9} + 1 × 2^{8} + 1 × 2^{7} + 1 × 2^{6} + 1 × 2^{5} + 1 × 2^{4} + 1 × 2^{3} + 0 × 2^{2} + 1 × 2^{1} + 1 × 2^{0})_{(10)} =

#### (0 + 0 + 0 + 0 + 0 + 0 + 0 + 0 + 0 + 0 + 0 + 0 + 0 + 0 + 131 072 + 65 536 + 32 768 + 16 384 + 8 192 + 4 096 + 2 048 + 1 024 + 512 + 256 + 128 + 64 + 32 + 16 + 8 + 0 + 2 + 1)_{(10)} =

#### (131 072 + 65 536 + 32 768 + 16 384 + 8 192 + 4 096 + 2 048 + 1 024 + 512 + 256 + 128 + 64 + 32 + 16 + 8 + 2 + 1)_{(10)} =

#### 262 139_{(10)}

### 5. If needed, adjust the sign of the integer number by the first digit (leftmost) of the signed binary:

#### 0000 0000 0000 0011 1111 1111 1111 1011_{(2)} = 262 139_{(10)}

## The signed binary number in one's complement representation 0000 0000 0000 0011 1111 1111 1111 1011_{(2)} converted and written as an integer in decimal system (base ten):

0000 0000 0000 0011 1111 1111 1111 1011_{(2)} = 262 139_{(10)}

Spaces were used to group digits: for binary, by 4, for decimal, by 3.