How to convert the base ten signed integer number 94 012 539 142 126 to base two:
- A signed integer, written in base ten, or a decimal system number, is a number written using the digits 0 through 9 and the sign, which can be positive (+) or negative (-). If positive, the sign is usually not written. A number written in base two, or binary, is a number written using only the digits 0 and 1.
To convert a base ten signed number (written as an integer in decimal system) to base two, written as a signed binary, follow the steps below.
- Divide the number repeatedly by 2: keep track of each remainder.
- Stop when you get a quotient that is equal to zero.
- Construct the base 2 representation of the positive number: take all the remainders starting from the bottom of the list constructed above.
- Determine the signed binary number bit length.
- Get the binary computer representation: if needed, add extra 0s in front (to the left) of the base 2 number, up to the required length and change the first bit (the leftmost), from 0 to 1, if the number is negative.
- Below you can see the conversion process to a signed binary and the related calculations.
1. Divide the number repeatedly by 2:
Keep track of each remainder.
Stop when you get a quotient that is equal to zero.
- division = quotient + remainder;
- 94 012 539 142 126 ÷ 2 = 47 006 269 571 063 + 0;
- 47 006 269 571 063 ÷ 2 = 23 503 134 785 531 + 1;
- 23 503 134 785 531 ÷ 2 = 11 751 567 392 765 + 1;
- 11 751 567 392 765 ÷ 2 = 5 875 783 696 382 + 1;
- 5 875 783 696 382 ÷ 2 = 2 937 891 848 191 + 0;
- 2 937 891 848 191 ÷ 2 = 1 468 945 924 095 + 1;
- 1 468 945 924 095 ÷ 2 = 734 472 962 047 + 1;
- 734 472 962 047 ÷ 2 = 367 236 481 023 + 1;
- 367 236 481 023 ÷ 2 = 183 618 240 511 + 1;
- 183 618 240 511 ÷ 2 = 91 809 120 255 + 1;
- 91 809 120 255 ÷ 2 = 45 904 560 127 + 1;
- 45 904 560 127 ÷ 2 = 22 952 280 063 + 1;
- 22 952 280 063 ÷ 2 = 11 476 140 031 + 1;
- 11 476 140 031 ÷ 2 = 5 738 070 015 + 1;
- 5 738 070 015 ÷ 2 = 2 869 035 007 + 1;
- 2 869 035 007 ÷ 2 = 1 434 517 503 + 1;
- 1 434 517 503 ÷ 2 = 717 258 751 + 1;
- 717 258 751 ÷ 2 = 358 629 375 + 1;
- 358 629 375 ÷ 2 = 179 314 687 + 1;
- 179 314 687 ÷ 2 = 89 657 343 + 1;
- 89 657 343 ÷ 2 = 44 828 671 + 1;
- 44 828 671 ÷ 2 = 22 414 335 + 1;
- 22 414 335 ÷ 2 = 11 207 167 + 1;
- 11 207 167 ÷ 2 = 5 603 583 + 1;
- 5 603 583 ÷ 2 = 2 801 791 + 1;
- 2 801 791 ÷ 2 = 1 400 895 + 1;
- 1 400 895 ÷ 2 = 700 447 + 1;
- 700 447 ÷ 2 = 350 223 + 1;
- 350 223 ÷ 2 = 175 111 + 1;
- 175 111 ÷ 2 = 87 555 + 1;
- 87 555 ÷ 2 = 43 777 + 1;
- 43 777 ÷ 2 = 21 888 + 1;
- 21 888 ÷ 2 = 10 944 + 0;
- 10 944 ÷ 2 = 5 472 + 0;
- 5 472 ÷ 2 = 2 736 + 0;
- 2 736 ÷ 2 = 1 368 + 0;
- 1 368 ÷ 2 = 684 + 0;
- 684 ÷ 2 = 342 + 0;
- 342 ÷ 2 = 171 + 0;
- 171 ÷ 2 = 85 + 1;
- 85 ÷ 2 = 42 + 1;
- 42 ÷ 2 = 21 + 0;
- 21 ÷ 2 = 10 + 1;
- 10 ÷ 2 = 5 + 0;
- 5 ÷ 2 = 2 + 1;
- 2 ÷ 2 = 1 + 0;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
94 012 539 142 126(10) = 101 0101 1000 0000 1111 1111 1111 1111 1111 1111 1110 1110(2)
3. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 47.
- A signed binary's bit length must be equal to a power of 2, as of:
- 21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
- The first bit (the leftmost) is reserved for the sign:
- 0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 47,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 64.
4. Get the positive binary computer representation on 64 bits (8 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 64:
Number 94 012 539 142 126(10), a signed integer number (with sign),
converted from decimal system (from base 10)
and written as a signed binary (in base 2):
94 012 539 142 126(10) = 0000 0000 0000 0000 0101 0101 1000 0000 1111 1111 1111 1111 1111 1111 1110 1110
Spaces were used to group digits: for binary, by 4, for decimal, by 3.