Signed: Integer -> Binary: 281 470 681 808 853 Convert the Integer Number to a Signed Binary. Converting and Writing the Base Ten Decimal System Signed Integer as Binary Code (Written in Base Two)
Signed integer number 281 470 681 808 853(10)
converted and written as a signed binary (base 2) = ?
1. Divide the number repeatedly by 2:
Keep track of each remainder.
We stop when we get a quotient that is equal to zero.
- division = quotient + remainder;
- 281 470 681 808 853 ÷ 2 = 140 735 340 904 426 + 1;
- 140 735 340 904 426 ÷ 2 = 70 367 670 452 213 + 0;
- 70 367 670 452 213 ÷ 2 = 35 183 835 226 106 + 1;
- 35 183 835 226 106 ÷ 2 = 17 591 917 613 053 + 0;
- 17 591 917 613 053 ÷ 2 = 8 795 958 806 526 + 1;
- 8 795 958 806 526 ÷ 2 = 4 397 979 403 263 + 0;
- 4 397 979 403 263 ÷ 2 = 2 198 989 701 631 + 1;
- 2 198 989 701 631 ÷ 2 = 1 099 494 850 815 + 1;
- 1 099 494 850 815 ÷ 2 = 549 747 425 407 + 1;
- 549 747 425 407 ÷ 2 = 274 873 712 703 + 1;
- 274 873 712 703 ÷ 2 = 137 436 856 351 + 1;
- 137 436 856 351 ÷ 2 = 68 718 428 175 + 1;
- 68 718 428 175 ÷ 2 = 34 359 214 087 + 1;
- 34 359 214 087 ÷ 2 = 17 179 607 043 + 1;
- 17 179 607 043 ÷ 2 = 8 589 803 521 + 1;
- 8 589 803 521 ÷ 2 = 4 294 901 760 + 1;
- 4 294 901 760 ÷ 2 = 2 147 450 880 + 0;
- 2 147 450 880 ÷ 2 = 1 073 725 440 + 0;
- 1 073 725 440 ÷ 2 = 536 862 720 + 0;
- 536 862 720 ÷ 2 = 268 431 360 + 0;
- 268 431 360 ÷ 2 = 134 215 680 + 0;
- 134 215 680 ÷ 2 = 67 107 840 + 0;
- 67 107 840 ÷ 2 = 33 553 920 + 0;
- 33 553 920 ÷ 2 = 16 776 960 + 0;
- 16 776 960 ÷ 2 = 8 388 480 + 0;
- 8 388 480 ÷ 2 = 4 194 240 + 0;
- 4 194 240 ÷ 2 = 2 097 120 + 0;
- 2 097 120 ÷ 2 = 1 048 560 + 0;
- 1 048 560 ÷ 2 = 524 280 + 0;
- 524 280 ÷ 2 = 262 140 + 0;
- 262 140 ÷ 2 = 131 070 + 0;
- 131 070 ÷ 2 = 65 535 + 0;
- 65 535 ÷ 2 = 32 767 + 1;
- 32 767 ÷ 2 = 16 383 + 1;
- 16 383 ÷ 2 = 8 191 + 1;
- 8 191 ÷ 2 = 4 095 + 1;
- 4 095 ÷ 2 = 2 047 + 1;
- 2 047 ÷ 2 = 1 023 + 1;
- 1 023 ÷ 2 = 511 + 1;
- 511 ÷ 2 = 255 + 1;
- 255 ÷ 2 = 127 + 1;
- 127 ÷ 2 = 63 + 1;
- 63 ÷ 2 = 31 + 1;
- 31 ÷ 2 = 15 + 1;
- 15 ÷ 2 = 7 + 1;
- 7 ÷ 2 = 3 + 1;
- 3 ÷ 2 = 1 + 1;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
281 470 681 808 853(10) = 1111 1111 1111 1111 0000 0000 0000 0000 1111 1111 1101 0101(2)
3. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 48.
A signed binary's bit length must be equal to a power of 2, as of:
21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
The first bit (the leftmost) is reserved for the sign:
0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 48,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 64.
4. Get the positive binary computer representation on 64 bits (8 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 64:
Number 281 470 681 808 853(10), a signed integer number (with sign),
converted from decimal system (from base 10)
and written as a signed binary (in base 2):
281 470 681 808 853(10) = 0000 0000 0000 0000 1111 1111 1111 1111 0000 0000 0000 0000 1111 1111 1101 0101
The first bit (the leftmost) is reserved for the sign:
0 = positive integer number, 1 = negative integer number
Spaces were used to group digits: for binary, by 4, for decimal, by 3.
Convert signed integer numbers from the decimal system (base ten) to signed binary (written in base two)
How to convert a base ten signed integer number to signed binary:
1) Divide the positive version of the number repeatedly by 2, keeping track of each remainder. Stop when getting a quotient that is 0.
2) Construct the base two representation by taking the previously calculated remainders starting from the last remainder up to the first one.
3) Construct the positive binary computer representation so that the first bit is 0.
4) Only if the initial number is negative, change the first bit (the leftmost), from 0 to 1. The leftmost bit is reserved for the sign, 1 = negative, 0 = positive.