1. Divide the number repeatedly by 2:
Keep track of each remainder.
We stop when we get a quotient that is equal to zero.
- division = quotient + remainder;
- 18 042 003 ÷ 2 = 9 021 001 + 1;
- 9 021 001 ÷ 2 = 4 510 500 + 1;
- 4 510 500 ÷ 2 = 2 255 250 + 0;
- 2 255 250 ÷ 2 = 1 127 625 + 0;
- 1 127 625 ÷ 2 = 563 812 + 1;
- 563 812 ÷ 2 = 281 906 + 0;
- 281 906 ÷ 2 = 140 953 + 0;
- 140 953 ÷ 2 = 70 476 + 1;
- 70 476 ÷ 2 = 35 238 + 0;
- 35 238 ÷ 2 = 17 619 + 0;
- 17 619 ÷ 2 = 8 809 + 1;
- 8 809 ÷ 2 = 4 404 + 1;
- 4 404 ÷ 2 = 2 202 + 0;
- 2 202 ÷ 2 = 1 101 + 0;
- 1 101 ÷ 2 = 550 + 1;
- 550 ÷ 2 = 275 + 0;
- 275 ÷ 2 = 137 + 1;
- 137 ÷ 2 = 68 + 1;
- 68 ÷ 2 = 34 + 0;
- 34 ÷ 2 = 17 + 0;
- 17 ÷ 2 = 8 + 1;
- 8 ÷ 2 = 4 + 0;
- 4 ÷ 2 = 2 + 0;
- 2 ÷ 2 = 1 + 0;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
18 042 003(10) = 1 0001 0011 0100 1100 1001 0011(2)
3. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 25.
A signed binary's bit length must be equal to a power of 2, as of:
21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
The first bit (the leftmost) is reserved for the sign:
0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 25,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 32.
4. Get the positive binary computer representation on 32 bits (4 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 32:
Number 18 042 003(10), a signed integer number (with sign),
converted from decimal system (from base 10)
and written as a signed binary (in base 2):
18 042 003(10) = 0000 0001 0001 0011 0100 1100 1001 0011
Spaces were used to group digits: for binary, by 4, for decimal, by 3.