1. Divide the number repeatedly by 2:
Keep track of each remainder.
We stop when we get a quotient that is equal to zero.
- division = quotient + remainder;
- 12 082 067 ÷ 2 = 6 041 033 + 1;
- 6 041 033 ÷ 2 = 3 020 516 + 1;
- 3 020 516 ÷ 2 = 1 510 258 + 0;
- 1 510 258 ÷ 2 = 755 129 + 0;
- 755 129 ÷ 2 = 377 564 + 1;
- 377 564 ÷ 2 = 188 782 + 0;
- 188 782 ÷ 2 = 94 391 + 0;
- 94 391 ÷ 2 = 47 195 + 1;
- 47 195 ÷ 2 = 23 597 + 1;
- 23 597 ÷ 2 = 11 798 + 1;
- 11 798 ÷ 2 = 5 899 + 0;
- 5 899 ÷ 2 = 2 949 + 1;
- 2 949 ÷ 2 = 1 474 + 1;
- 1 474 ÷ 2 = 737 + 0;
- 737 ÷ 2 = 368 + 1;
- 368 ÷ 2 = 184 + 0;
- 184 ÷ 2 = 92 + 0;
- 92 ÷ 2 = 46 + 0;
- 46 ÷ 2 = 23 + 0;
- 23 ÷ 2 = 11 + 1;
- 11 ÷ 2 = 5 + 1;
- 5 ÷ 2 = 2 + 1;
- 2 ÷ 2 = 1 + 0;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
12 082 067(10) = 1011 1000 0101 1011 1001 0011(2)
3. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 24.
A signed binary's bit length must be equal to a power of 2, as of:
21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
The first bit (the leftmost) is reserved for the sign:
0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 24,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 32.
4. Get the positive binary computer representation on 32 bits (4 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 32:
Number 12 082 067(10), a signed integer number (with sign),
converted from decimal system (from base 10)
and written as a signed binary (in base 2):
12 082 067(10) = 0000 0000 1011 1000 0101 1011 1001 0011
Spaces were used to group digits: for binary, by 4, for decimal, by 3.