# Convert 1 011 101 014 to signed binary, from a base 10 decimal system signed integer number

## How to convert the signed integer in decimal system (in base 10): 1 011 101 014(10)to a signed binary

### 1. Divide the number repeatedly by 2:

#### We stop when we get a quotient that is equal to zero.

• division = quotient + remainder;
• 1 011 101 014 ÷ 2 = 505 550 507 + 0;
• 505 550 507 ÷ 2 = 252 775 253 + 1;
• 252 775 253 ÷ 2 = 126 387 626 + 1;
• 126 387 626 ÷ 2 = 63 193 813 + 0;
• 63 193 813 ÷ 2 = 31 596 906 + 1;
• 31 596 906 ÷ 2 = 15 798 453 + 0;
• 15 798 453 ÷ 2 = 7 899 226 + 1;
• 7 899 226 ÷ 2 = 3 949 613 + 0;
• 3 949 613 ÷ 2 = 1 974 806 + 1;
• 1 974 806 ÷ 2 = 987 403 + 0;
• 987 403 ÷ 2 = 493 701 + 1;
• 493 701 ÷ 2 = 246 850 + 1;
• 246 850 ÷ 2 = 123 425 + 0;
• 123 425 ÷ 2 = 61 712 + 1;
• 61 712 ÷ 2 = 30 856 + 0;
• 30 856 ÷ 2 = 15 428 + 0;
• 15 428 ÷ 2 = 7 714 + 0;
• 7 714 ÷ 2 = 3 857 + 0;
• 3 857 ÷ 2 = 1 928 + 1;
• 1 928 ÷ 2 = 964 + 0;
• 964 ÷ 2 = 482 + 0;
• 482 ÷ 2 = 241 + 0;
• 241 ÷ 2 = 120 + 1;
• 120 ÷ 2 = 60 + 0;
• 60 ÷ 2 = 30 + 0;
• 30 ÷ 2 = 15 + 0;
• 15 ÷ 2 = 7 + 1;
• 7 ÷ 2 = 3 + 1;
• 3 ÷ 2 = 1 + 1;
• 1 ÷ 2 = 0 + 1;

## Latest signed integer numbers in decimal (base ten) converted to signed binary

 1,011,101,014 to signed binary = ? Nov 29 22:26 UTC (GMT) 12,382 to signed binary = ? Nov 29 22:26 UTC (GMT) 12,368 to signed binary = ? Nov 29 22:26 UTC (GMT) 123,663 to signed binary = ? Nov 29 22:25 UTC (GMT) 123,655 to signed binary = ? Nov 29 22:25 UTC (GMT) 42,949,676,002 to signed binary = ? Nov 29 22:25 UTC (GMT) 123,602 to signed binary = ? Nov 29 22:25 UTC (GMT) -1,608,786,305 to signed binary = ? Nov 29 22:25 UTC (GMT) 123,594 to signed binary = ? Nov 29 22:25 UTC (GMT) 123,581 to signed binary = ? Nov 29 22:25 UTC (GMT) 12,355 to signed binary = ? Nov 29 22:25 UTC (GMT) 42,949,675,996 to signed binary = ? Nov 29 22:25 UTC (GMT) 123,456,789,987,654,329 to signed binary = ? Nov 29 22:25 UTC (GMT) All decimal positive integers converted to signed binary

## How to convert signed integers from decimal system to binary code system

### Follow the steps below to convert a signed base ten integer number to signed binary:

• 1. In a signed binary, first bit (the leftmost) is reserved for sign: 0 = positive integer number, 1 = positive integer number. If the number to be converted is negative, start with its positive version.
• 2. Divide repeatedly by 2 the positive integer number keeping track of each remainder. STOP when we get a quotient that is ZERO.
• 3. Construct the base 2 representation of the positive number, by taking all the remainders starting from the bottom of the list constructed above. Thus, the last remainder of the divisions becomes the first symbol (the leftmost) of the base two number, while the first remainder becomes the last symbol (the rightmost).
• 4. Binary numbers represented in computer language have a length of 4, 8, 16, 32, 64, ... bits (power of 2) - if needed, fill in extra '0' bits in front of the base 2 number (to the left), up to the right length; this way the first bit (the leftmost one) is always '0', as for a positive representation.
• 5. To get the negative reprezentation of the number, simply switch the first bit (the leftmost one), from '0' to '1'.

### Example: convert the negative number -63 from decimal system (base ten) to signed binary code system:

• 1. Start with the positive version of the number: |-63| = 63;
• 2. Divide repeatedly 63 by 2, keeping track of each remainder, until we get a quotient that is equal to zero:
• division = quotient + remainder
• 63 ÷ 2 = 31 + 1
• 31 ÷ 2 = 15 + 1
• 15 ÷ 2 = 7 + 1
• 7 ÷ 2 = 3 + 1
• 3 ÷ 2 = 1 + 1
• 1 ÷ 2 = 0 + 1
• 3. Construct the base 2 representation of the positive number, by taking all the remainders starting from the bottom of the list constructed above:
63(10) = 11 1111(2)
• 4. The actual length of base 2 representation number is 6, so the positive binary computer representation length of the signed binary will take in this case 8 bits (the least power of 2 higher than 6) - add extra '0's in front (to the left), up to the required length; this way the first bit (the leftmost one) is to be '0', as for a positive number:
63(10) = 0011 1111(2)
• 5. To get the negative integer number representation simply change the first bit (the leftmost), from '0' to '1':
-63(10) = 1011 1111