What are the required steps to convert base 10 integer
number 1 010 110 110 009 325 to signed binary code (in base 2)?
- A signed integer, written in base ten, or a decimal system number, is a number written using the digits 0 through 9 and the sign, which can be positive (+) or negative (-). If positive, the sign is usually not written. A number written in base two, or binary, is a number written using only the digits 0 and 1.
1. Divide the number repeatedly by 2:
Keep track of each remainder.
Stop when you get a quotient that is equal to zero.
- division = quotient + remainder;
- 1 010 110 110 009 325 ÷ 2 = 505 055 055 004 662 + 1;
- 505 055 055 004 662 ÷ 2 = 252 527 527 502 331 + 0;
- 252 527 527 502 331 ÷ 2 = 126 263 763 751 165 + 1;
- 126 263 763 751 165 ÷ 2 = 63 131 881 875 582 + 1;
- 63 131 881 875 582 ÷ 2 = 31 565 940 937 791 + 0;
- 31 565 940 937 791 ÷ 2 = 15 782 970 468 895 + 1;
- 15 782 970 468 895 ÷ 2 = 7 891 485 234 447 + 1;
- 7 891 485 234 447 ÷ 2 = 3 945 742 617 223 + 1;
- 3 945 742 617 223 ÷ 2 = 1 972 871 308 611 + 1;
- 1 972 871 308 611 ÷ 2 = 986 435 654 305 + 1;
- 986 435 654 305 ÷ 2 = 493 217 827 152 + 1;
- 493 217 827 152 ÷ 2 = 246 608 913 576 + 0;
- 246 608 913 576 ÷ 2 = 123 304 456 788 + 0;
- 123 304 456 788 ÷ 2 = 61 652 228 394 + 0;
- 61 652 228 394 ÷ 2 = 30 826 114 197 + 0;
- 30 826 114 197 ÷ 2 = 15 413 057 098 + 1;
- 15 413 057 098 ÷ 2 = 7 706 528 549 + 0;
- 7 706 528 549 ÷ 2 = 3 853 264 274 + 1;
- 3 853 264 274 ÷ 2 = 1 926 632 137 + 0;
- 1 926 632 137 ÷ 2 = 963 316 068 + 1;
- 963 316 068 ÷ 2 = 481 658 034 + 0;
- 481 658 034 ÷ 2 = 240 829 017 + 0;
- 240 829 017 ÷ 2 = 120 414 508 + 1;
- 120 414 508 ÷ 2 = 60 207 254 + 0;
- 60 207 254 ÷ 2 = 30 103 627 + 0;
- 30 103 627 ÷ 2 = 15 051 813 + 1;
- 15 051 813 ÷ 2 = 7 525 906 + 1;
- 7 525 906 ÷ 2 = 3 762 953 + 0;
- 3 762 953 ÷ 2 = 1 881 476 + 1;
- 1 881 476 ÷ 2 = 940 738 + 0;
- 940 738 ÷ 2 = 470 369 + 0;
- 470 369 ÷ 2 = 235 184 + 1;
- 235 184 ÷ 2 = 117 592 + 0;
- 117 592 ÷ 2 = 58 796 + 0;
- 58 796 ÷ 2 = 29 398 + 0;
- 29 398 ÷ 2 = 14 699 + 0;
- 14 699 ÷ 2 = 7 349 + 1;
- 7 349 ÷ 2 = 3 674 + 1;
- 3 674 ÷ 2 = 1 837 + 0;
- 1 837 ÷ 2 = 918 + 1;
- 918 ÷ 2 = 459 + 0;
- 459 ÷ 2 = 229 + 1;
- 229 ÷ 2 = 114 + 1;
- 114 ÷ 2 = 57 + 0;
- 57 ÷ 2 = 28 + 1;
- 28 ÷ 2 = 14 + 0;
- 14 ÷ 2 = 7 + 0;
- 7 ÷ 2 = 3 + 1;
- 3 ÷ 2 = 1 + 1;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
1 010 110 110 009 325(10) = 11 1001 0110 1011 0000 1001 0110 0100 1010 1000 0111 1110 1101(2)
3. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 50.
- A signed binary's bit length must be equal to a power of 2, as of:
- 21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
- The first bit (the leftmost) is reserved for the sign:
- 0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 50,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 64.
4. Get the positive binary computer representation on 64 bits (8 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 64:
1 010 110 110 009 325(10) Base 10 integer number converted and written as a signed binary code (in base 2):
1 010 110 110 009 325(10) = 0000 0000 0000 0011 1001 0110 1011 0000 1001 0110 0100 1010 1000 0111 1110 1101
Spaces were used to group digits: for binary, by 4, for decimal, by 3.