1. Divide the number repeatedly by 2:
Keep track of each remainder.
We stop when we get a quotient that is equal to zero.
- division = quotient + remainder;
- 100 001 001 110 106 ÷ 2 = 50 000 500 555 053 + 0;
- 50 000 500 555 053 ÷ 2 = 25 000 250 277 526 + 1;
- 25 000 250 277 526 ÷ 2 = 12 500 125 138 763 + 0;
- 12 500 125 138 763 ÷ 2 = 6 250 062 569 381 + 1;
- 6 250 062 569 381 ÷ 2 = 3 125 031 284 690 + 1;
- 3 125 031 284 690 ÷ 2 = 1 562 515 642 345 + 0;
- 1 562 515 642 345 ÷ 2 = 781 257 821 172 + 1;
- 781 257 821 172 ÷ 2 = 390 628 910 586 + 0;
- 390 628 910 586 ÷ 2 = 195 314 455 293 + 0;
- 195 314 455 293 ÷ 2 = 97 657 227 646 + 1;
- 97 657 227 646 ÷ 2 = 48 828 613 823 + 0;
- 48 828 613 823 ÷ 2 = 24 414 306 911 + 1;
- 24 414 306 911 ÷ 2 = 12 207 153 455 + 1;
- 12 207 153 455 ÷ 2 = 6 103 576 727 + 1;
- 6 103 576 727 ÷ 2 = 3 051 788 363 + 1;
- 3 051 788 363 ÷ 2 = 1 525 894 181 + 1;
- 1 525 894 181 ÷ 2 = 762 947 090 + 1;
- 762 947 090 ÷ 2 = 381 473 545 + 0;
- 381 473 545 ÷ 2 = 190 736 772 + 1;
- 190 736 772 ÷ 2 = 95 368 386 + 0;
- 95 368 386 ÷ 2 = 47 684 193 + 0;
- 47 684 193 ÷ 2 = 23 842 096 + 1;
- 23 842 096 ÷ 2 = 11 921 048 + 0;
- 11 921 048 ÷ 2 = 5 960 524 + 0;
- 5 960 524 ÷ 2 = 2 980 262 + 0;
- 2 980 262 ÷ 2 = 1 490 131 + 0;
- 1 490 131 ÷ 2 = 745 065 + 1;
- 745 065 ÷ 2 = 372 532 + 1;
- 372 532 ÷ 2 = 186 266 + 0;
- 186 266 ÷ 2 = 93 133 + 0;
- 93 133 ÷ 2 = 46 566 + 1;
- 46 566 ÷ 2 = 23 283 + 0;
- 23 283 ÷ 2 = 11 641 + 1;
- 11 641 ÷ 2 = 5 820 + 1;
- 5 820 ÷ 2 = 2 910 + 0;
- 2 910 ÷ 2 = 1 455 + 0;
- 1 455 ÷ 2 = 727 + 1;
- 727 ÷ 2 = 363 + 1;
- 363 ÷ 2 = 181 + 1;
- 181 ÷ 2 = 90 + 1;
- 90 ÷ 2 = 45 + 0;
- 45 ÷ 2 = 22 + 1;
- 22 ÷ 2 = 11 + 0;
- 11 ÷ 2 = 5 + 1;
- 5 ÷ 2 = 2 + 1;
- 2 ÷ 2 = 1 + 0;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
100 001 001 110 106(10) = 101 1010 1111 0011 0100 1100 0010 0101 1111 1010 0101 1010(2)
3. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 47.
A signed binary's bit length must be equal to a power of 2, as of:
21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
The first bit (the leftmost) is reserved for the sign:
0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 47,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 64.
4. Get the positive binary computer representation on 64 bits (8 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 64:
Number 100 001 001 110 106(10), a signed integer number (with sign),
converted from decimal system (from base 10)
and written as a signed binary (in base 2):
100 001 001 110 106(10) = 0000 0000 0000 0000 0101 1010 1111 0011 0100 1100 0010 0101 1111 1010 0101 1010
Spaces were used to group digits: for binary, by 4, for decimal, by 3.