1. Divide the number repeatedly by 2:
Keep track of each remainder.
We stop when we get a quotient that is equal to zero.
- division = quotient + remainder;
- 922 342 955 ÷ 2 = 461 171 477 + 1;
- 461 171 477 ÷ 2 = 230 585 738 + 1;
- 230 585 738 ÷ 2 = 115 292 869 + 0;
- 115 292 869 ÷ 2 = 57 646 434 + 1;
- 57 646 434 ÷ 2 = 28 823 217 + 0;
- 28 823 217 ÷ 2 = 14 411 608 + 1;
- 14 411 608 ÷ 2 = 7 205 804 + 0;
- 7 205 804 ÷ 2 = 3 602 902 + 0;
- 3 602 902 ÷ 2 = 1 801 451 + 0;
- 1 801 451 ÷ 2 = 900 725 + 1;
- 900 725 ÷ 2 = 450 362 + 1;
- 450 362 ÷ 2 = 225 181 + 0;
- 225 181 ÷ 2 = 112 590 + 1;
- 112 590 ÷ 2 = 56 295 + 0;
- 56 295 ÷ 2 = 28 147 + 1;
- 28 147 ÷ 2 = 14 073 + 1;
- 14 073 ÷ 2 = 7 036 + 1;
- 7 036 ÷ 2 = 3 518 + 0;
- 3 518 ÷ 2 = 1 759 + 0;
- 1 759 ÷ 2 = 879 + 1;
- 879 ÷ 2 = 439 + 1;
- 439 ÷ 2 = 219 + 1;
- 219 ÷ 2 = 109 + 1;
- 109 ÷ 2 = 54 + 1;
- 54 ÷ 2 = 27 + 0;
- 27 ÷ 2 = 13 + 1;
- 13 ÷ 2 = 6 + 1;
- 6 ÷ 2 = 3 + 0;
- 3 ÷ 2 = 1 + 1;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
922 342 955(10) = 11 0110 1111 1001 1101 0110 0010 1011(2)
3. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 30.
- A signed binary's bit length must be equal to a power of 2, as of:
- 21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
- The first bit (the leftmost) indicates the sign:
- 0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 30,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 32.
4. Get the positive binary computer representation on 32 bits (4 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 32.
Decimal Number 922 342 955(10) converted to signed binary in two's complement representation:
Spaces were used to group digits: for binary, by 4, for decimal, by 3.