1. Divide the number repeatedly by 2:
Keep track of each remainder.
We stop when we get a quotient that is equal to zero.
- division = quotient + remainder;
- 110 100 ÷ 2 = 55 050 + 0;
- 55 050 ÷ 2 = 27 525 + 0;
- 27 525 ÷ 2 = 13 762 + 1;
- 13 762 ÷ 2 = 6 881 + 0;
- 6 881 ÷ 2 = 3 440 + 1;
- 3 440 ÷ 2 = 1 720 + 0;
- 1 720 ÷ 2 = 860 + 0;
- 860 ÷ 2 = 430 + 0;
- 430 ÷ 2 = 215 + 0;
- 215 ÷ 2 = 107 + 1;
- 107 ÷ 2 = 53 + 1;
- 53 ÷ 2 = 26 + 1;
- 26 ÷ 2 = 13 + 0;
- 13 ÷ 2 = 6 + 1;
- 6 ÷ 2 = 3 + 0;
- 3 ÷ 2 = 1 + 1;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
110 100(10) = 1 1010 1110 0001 0100(2)
3. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 17.
A signed binary's bit length must be equal to a power of 2, as of:
21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
The first bit (the leftmost) indicates the sign:
0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 17,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 32.
4. Get the positive binary computer representation on 32 bits (4 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 32.
Number 110 100(10), a signed integer number (with sign), converted from decimal system (from base 10) and written as a signed binary in two's complement representation:
Spaces were used to group digits: for binary, by 4, for decimal, by 3.