1. Divide the number repeatedly by 2:
Keep track of each remainder.
We stop when we get a quotient that is equal to zero.
- division = quotient + remainder;
- 1 241 514 014 ÷ 2 = 620 757 007 + 0;
- 620 757 007 ÷ 2 = 310 378 503 + 1;
- 310 378 503 ÷ 2 = 155 189 251 + 1;
- 155 189 251 ÷ 2 = 77 594 625 + 1;
- 77 594 625 ÷ 2 = 38 797 312 + 1;
- 38 797 312 ÷ 2 = 19 398 656 + 0;
- 19 398 656 ÷ 2 = 9 699 328 + 0;
- 9 699 328 ÷ 2 = 4 849 664 + 0;
- 4 849 664 ÷ 2 = 2 424 832 + 0;
- 2 424 832 ÷ 2 = 1 212 416 + 0;
- 1 212 416 ÷ 2 = 606 208 + 0;
- 606 208 ÷ 2 = 303 104 + 0;
- 303 104 ÷ 2 = 151 552 + 0;
- 151 552 ÷ 2 = 75 776 + 0;
- 75 776 ÷ 2 = 37 888 + 0;
- 37 888 ÷ 2 = 18 944 + 0;
- 18 944 ÷ 2 = 9 472 + 0;
- 9 472 ÷ 2 = 4 736 + 0;
- 4 736 ÷ 2 = 2 368 + 0;
- 2 368 ÷ 2 = 1 184 + 0;
- 1 184 ÷ 2 = 592 + 0;
- 592 ÷ 2 = 296 + 0;
- 296 ÷ 2 = 148 + 0;
- 148 ÷ 2 = 74 + 0;
- 74 ÷ 2 = 37 + 0;
- 37 ÷ 2 = 18 + 1;
- 18 ÷ 2 = 9 + 0;
- 9 ÷ 2 = 4 + 1;
- 4 ÷ 2 = 2 + 0;
- 2 ÷ 2 = 1 + 0;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
1 241 514 014(10) = 100 1010 0000 0000 0000 0000 0001 1110(2)
3. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 31.
A signed binary's bit length must be equal to a power of 2, as of:
21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
The first bit (the leftmost) indicates the sign:
0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 31,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 32.
4. Get the positive binary computer representation on 32 bits (4 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 32.
Number 1 241 514 014(10), a signed integer number (with sign), converted from decimal system (from base 10) and written as a signed binary in one's complement representation:
Spaces were used to group digits: for binary, by 4, for decimal, by 3.