-2 453(10) to a signed binary one's complement representation = ?
1. Start with the positive version of the number:
|-2 453| = 2 453
2. Divide the number repeatedly by 2:
Keep track of each remainder.
We stop when we get a quotient that is equal to zero.
- division = quotient + remainder;
- 2 453 ÷ 2 = 1 226 + 1;
- 1 226 ÷ 2 = 613 + 0;
- 613 ÷ 2 = 306 + 1;
- 306 ÷ 2 = 153 + 0;
- 153 ÷ 2 = 76 + 1;
- 76 ÷ 2 = 38 + 0;
- 38 ÷ 2 = 19 + 0;
- 19 ÷ 2 = 9 + 1;
- 9 ÷ 2 = 4 + 1;
- 4 ÷ 2 = 2 + 0;
- 2 ÷ 2 = 1 + 0;
- 1 ÷ 2 = 0 + 1;
3. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
2 453(10) = 1001 1001 0101(2)
4. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 12.
A signed binary's bit length must be equal to a power of 2, as of:
21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
First bit (the leftmost) indicates the sign,
1 = negative, 0 = positive.
The least number that is:
a power of 2
and is larger than the actual length, 12,
so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
is: 16.
5. Positive binary computer representation on 16 bits (2 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 16:
2 453(10) = 0000 1001 1001 0101
6. Get the negative integer number representation:
To get the negative integer number representation on 16 bits (2 Bytes),
signed binary one's complement,
replace all the bits on 0 with 1s
and all the bits set on 1 with 0s
(reverse the digits, flip the digits)
!(0000 1001 1001 0101) =
1111 0110 0110 1010
Number -2 453, a signed integer, converted from decimal system (base 10) to a signed binary one's complement representation:
-2 453(10) = 1111 0110 0110 1010
Spaces used to group digits: for binary, by 4; for decimal, by 3.
More operations of this kind:
Convert signed integer numbers from the decimal system (base ten) to signed binary one's complement representation