What are the required steps to convert base 10 decimal system
number 2 548 938 to base 2 unsigned binary equivalent?
- A number written in base ten, or a decimal system number, is a number written using the digits 0 through 9. A number written in base two, or a binary system number, is a number written using only the digits 0 and 1.
1. Divide the number repeatedly by 2:
Keep track of each remainder.
Stop when you get a quotient that is equal to zero.
- division = quotient + remainder;
- 2 548 938 ÷ 2 = 1 274 469 + 0;
- 1 274 469 ÷ 2 = 637 234 + 1;
- 637 234 ÷ 2 = 318 617 + 0;
- 318 617 ÷ 2 = 159 308 + 1;
- 159 308 ÷ 2 = 79 654 + 0;
- 79 654 ÷ 2 = 39 827 + 0;
- 39 827 ÷ 2 = 19 913 + 1;
- 19 913 ÷ 2 = 9 956 + 1;
- 9 956 ÷ 2 = 4 978 + 0;
- 4 978 ÷ 2 = 2 489 + 0;
- 2 489 ÷ 2 = 1 244 + 1;
- 1 244 ÷ 2 = 622 + 0;
- 622 ÷ 2 = 311 + 0;
- 311 ÷ 2 = 155 + 1;
- 155 ÷ 2 = 77 + 1;
- 77 ÷ 2 = 38 + 1;
- 38 ÷ 2 = 19 + 0;
- 19 ÷ 2 = 9 + 1;
- 9 ÷ 2 = 4 + 1;
- 4 ÷ 2 = 2 + 0;
- 2 ÷ 2 = 1 + 0;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
2 548 938(10) Base 10 decimal system number converted and written as a base 2 unsigned binary equivalent:
2 548 938 (base 10) = 10 0110 1110 0100 1100 1010 (base 2)
Spaces were used to group digits: for binary, by 4, for decimal, by 3.