Unsigned: Integer -> Binary: 149 613 Convert the Positive Integer (Whole Number) From Base Ten (10) To Base Two (2), Conversion and Writing of Decimal System Number as Unsigned Binary Code
Unsigned (positive) integer number 149 613(10)
converted and written as an unsigned binary (base 2) = ?
1. Divide the number repeatedly by 2:
Keep track of each remainder.
We stop when we get a quotient that is equal to zero.
- division = quotient + remainder;
- 149 613 ÷ 2 = 74 806 + 1;
- 74 806 ÷ 2 = 37 403 + 0;
- 37 403 ÷ 2 = 18 701 + 1;
- 18 701 ÷ 2 = 9 350 + 1;
- 9 350 ÷ 2 = 4 675 + 0;
- 4 675 ÷ 2 = 2 337 + 1;
- 2 337 ÷ 2 = 1 168 + 1;
- 1 168 ÷ 2 = 584 + 0;
- 584 ÷ 2 = 292 + 0;
- 292 ÷ 2 = 146 + 0;
- 146 ÷ 2 = 73 + 0;
- 73 ÷ 2 = 36 + 1;
- 36 ÷ 2 = 18 + 0;
- 18 ÷ 2 = 9 + 0;
- 9 ÷ 2 = 4 + 1;
- 4 ÷ 2 = 2 + 0;
- 2 ÷ 2 = 1 + 0;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
Number 149 613(10), a positive integer number (with no sign),
converted from decimal system (from base 10)
and written as an unsigned binary (in base 2):
149 613(10) = 10 0100 1000 0110 1101(2)
Spaces were used to group digits: for binary, by 4, for decimal, by 3.
Convert positive integer numbers (unsigned) from decimal system (base ten) to binary (base two)
How to convert a base 10 positive integer number to base 2:
1) Divide the number repeatedly by 2, keeping track of each remainder, until getting a quotient that is 0;
2) Construct the base 2 representation by taking all the previously calculated remainders starting from the last remainder up to the first one, in that order.