### 2. Multiply each bit by its corresponding power of 2 and add all the terms up.

#### 111 1101 1111 0011_{(2)} =

#### (1 × 2^{14} + 1 × 2^{13} + 1 × 2^{12} + 1 × 2^{11} + 1 × 2^{10} + 0 × 2^{9} + 1 × 2^{8} + 1 × 2^{7} + 1 × 2^{6} + 1 × 2^{5} + 1 × 2^{4} + 0 × 2^{3} + 0 × 2^{2} + 1 × 2^{1} + 1 × 2^{0})_{(10)} =

#### (16 384 + 8 192 + 4 096 + 2 048 + 1 024 + 0 + 256 + 128 + 64 + 32 + 16 + 0 + 0 + 2 + 1)_{(10)} =

#### (16 384 + 8 192 + 4 096 + 2 048 + 1 024 + 256 + 128 + 64 + 32 + 16 + 2 + 1)_{(10)} =

#### 32 243_{(10)}

## The number 111 1101 1111 0011_{(2)} converted from an unsigned binary (in base 2) and written as a positive integer (with no sign) in decimal system (in base ten):

111 1101 1111 0011_{(2)} = 32 243_{(10)}

Spaces were used to group digits: for binary, by 4, for decimal, by 3.