2. Multiply each bit by its corresponding power of 2 and add all the terms up.
11 1110 0000 0010 1100(2) =
(1 × 217 + 1 × 216 + 1 × 215 + 1 × 214 + 1 × 213 + 0 × 212 + 0 × 211 + 0 × 210 + 0 × 29 + 0 × 28 + 0 × 27 + 0 × 26 + 1 × 25 + 0 × 24 + 1 × 23 + 1 × 22 + 0 × 21 + 0 × 20)(10) =
(131 072 + 65 536 + 32 768 + 16 384 + 8 192 + 0 + 0 + 0 + 0 + 0 + 0 + 0 + 32 + 0 + 8 + 4 + 0 + 0)(10) =
(131 072 + 65 536 + 32 768 + 16 384 + 8 192 + 32 + 8 + 4)(10) =
253 996(10)
The number 11 1110 0000 0010 1100(2) converted from an unsigned binary (in base 2) and written as a positive integer (with no sign) in decimal system (in base ten):
11 1110 0000 0010 1100(2) = 253 996(10)
Spaces were used to group digits: for binary, by 4, for decimal, by 3.