2. Multiply each bit by its corresponding power of 2 and add all the terms up.
1 0100 1011 0100 1000 0010 0010(2) =
(1 × 224 + 0 × 223 + 1 × 222 + 0 × 221 + 0 × 220 + 1 × 219 + 0 × 218 + 1 × 217 + 1 × 216 + 0 × 215 + 1 × 214 + 0 × 213 + 0 × 212 + 1 × 211 + 0 × 210 + 0 × 29 + 0 × 28 + 0 × 27 + 0 × 26 + 1 × 25 + 0 × 24 + 0 × 23 + 0 × 22 + 1 × 21 + 0 × 20)(10) =
(16 777 216 + 0 + 4 194 304 + 0 + 0 + 524 288 + 0 + 131 072 + 65 536 + 0 + 16 384 + 0 + 0 + 2 048 + 0 + 0 + 0 + 0 + 0 + 32 + 0 + 0 + 0 + 2 + 0)(10) =
(16 777 216 + 4 194 304 + 524 288 + 131 072 + 65 536 + 16 384 + 2 048 + 32 + 2)(10) =
21 710 882(10)
The number 1 0100 1011 0100 1000 0010 0010(2) converted from an unsigned binary (in base 2) and written as a positive integer (with no sign) in decimal system (in base ten):
1 0100 1011 0100 1000 0010 0010(2) = 21 710 882(10)
Spaces were used to group digits: for binary, by 4, for decimal, by 3.