2. Multiply each bit by its corresponding power of 2 and add all the terms up.
10 0100 0110 1010 0101 0100(2) =
(1 × 221 + 0 × 220 + 0 × 219 + 1 × 218 + 0 × 217 + 0 × 216 + 0 × 215 + 1 × 214 + 1 × 213 + 0 × 212 + 1 × 211 + 0 × 210 + 1 × 29 + 0 × 28 + 0 × 27 + 1 × 26 + 0 × 25 + 1 × 24 + 0 × 23 + 1 × 22 + 0 × 21 + 0 × 20)(10) =
(2 097 152 + 0 + 0 + 262 144 + 0 + 0 + 0 + 16 384 + 8 192 + 0 + 2 048 + 0 + 512 + 0 + 0 + 64 + 0 + 16 + 0 + 4 + 0 + 0)(10) =
(2 097 152 + 262 144 + 16 384 + 8 192 + 2 048 + 512 + 64 + 16 + 4)(10) =
2 386 516(10)
The number 10 0100 0110 1010 0101 0100(2) converted from an unsigned binary (in base 2) and written as a positive integer (with no sign) in decimal system (in base ten):
10 0100 0110 1010 0101 0100(2) = 2 386 516(10)
Spaces were used to group digits: for binary, by 4, for decimal, by 3.